Thank you Martin. Is there no other way to preserve a sequence than to resort
to connecting the XSLT to an XML Schema?
In my actual application I am creating many sequences. I need an efficient way
of storing the sequences. For example, initially $list might be (1, 2, 3) and
then processing results in updating $list to (4, 1, 5) and then to (9, 9, 0)
and then to (4, 1, 4) and then to ...
What is your recommendation for managing sequences?
/Roger
-----Original Message-----
From: Martin Honnen martin(_dot_)honnen(_at_)gmx(_dot_)de
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Sunday, July 19, 2020 3:57 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [EXT] Re: [xsl] How to store a sequence into an element ... and
maintainthe sequence inside the element?
On 19.07.2020 21:14, Dr. Roger L Costello costello(_at_)mitre(_dot_)org wrote:
Hi Folks,
I created a sequence (1, 2, 3) as follows:
<xsl:variable name="list" select="(1, 2, 3)" as="xs:integer*" />
I checked that $list contains 3 integers:
<xsl:message>count($list) = <xsl:value-of
select="count($list)"/></xsl:message>
Sure enough, the output shows that there are 3 items:
count($list) = 3
Next, I want to store that sequence of integers in an element, along with
other elements:
<xsl:variable name="document" as="element(Document)">
<Document>
<Greeting>My List</Greeting>
<List><xsl:sequence select="$list" /></List>
<Ending>The End</Ending>
</Document>
</xsl:variable>
Does the <List> element contain a sequence of 3 integers:
<xsl:message>count($document/List) = <xsl:value-of
select="count($document/List)"/></xsl:message>
Yikes! No it doesn't:
count($document/List) = 1
How to do what I want to do? That is, how to store the sequence of integers
in an element, along with other elements, such that I can pull the sequence
out of the element and immediately operate on the sequence? If that can't be
done, then what's the right way to do what I want to do?
That expression will always return the number of "List" elements. If you
use a schema and give that element a list datatype then I think that
with schema-aware processing
$document/List/data()
would give you a list and you could of course count that list with e.g.
count($document/List/data())
So the simplest example would be
<xsl:import-schema>
<xs:schema>
<xs:element name="List" type="int-list"/>
<xs:simpleType name="int-list">
<xs:list itemType="xs:integer"/>
</xs:simpleType>
</xs:schema>
</xsl:import-schema>
<xsl:template match="/" name="xsl:initial-template">
<xsl:variable name="list" select="(1, 2, 3)" as="xs:integer*" />
<xsl:message>count($list) = <xsl:value-of
select="count($list)"/></xsl:message>
<xsl:variable name="list-element" as="schema-element(List)">
<List xsl:validation="strict">
<xsl:sequence select="$list"/>
</List>
</xsl:variable>
<xsl:message>count($list-element) = <xsl:value-of
select="count($list-element)"/></xsl:message>
<xsl:message>count($list-element/data()) = <xsl:value-of
select="count($list-element/data())"/></xsl:message>
<xsl:message select="$list-element instance of
schema-element(List)"/>
</xsl:template>
you would need to write a more complex schema for the more complex
sample you had I think, I am not sure whether you could use a schema
type for that element inside other untyped elements.
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