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Re: [xsl] How to store a sequence into an element ... and maintain the sequence inside the element?

2020-07-19 15:57:58
That's the point Liam was making last week - XML is very text-oriented. When 
you add a list of numbers to a document it gets serialized as a string. As 
Martin says, you can turn it back into a sequence of numbers by validating 
against a list type defined in a schema. But that's very limiting, which is why 
XSLT 3.0 introduced maps and arrays.

Michael Kay
Saxonica

On 19 Jul 2020, at 20:14, Dr. Roger L Costello costello(_at_)mitre(_dot_)org 
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:

Hi Folks,

I created a sequence (1, 2, 3) as follows:

<xsl:variable name="list" select="(1, 2, 3)" as="xs:integer*" />

I checked that $list contains 3 integers:

<xsl:message>count($list) = <xsl:value-of 
select="count($list)"/></xsl:message>

Sure enough, the output shows that there are 3 items:

count($list) = 3

Next, I want to store that sequence of integers in an element, along with 
other elements:

<xsl:variable name="document" as="element(Document)">
   <Document>
       <Greeting>My List</Greeting>
       <List><xsl:sequence select="$list" /></List>
       <Ending>The End</Ending>
   </Document>
</xsl:variable>

Does the <List> element contain a sequence of 3 integers:

<xsl:message>count($document/List) = <xsl:value-of 
select="count($document/List)"/></xsl:message>

Yikes! No it doesn't:

count($document/List) = 1

How to do what I want to do? That is, how to store the sequence of integers 
in an element, along with other elements, such that I can pull the sequence 
out of the element and immediately operate on the sequence? If that can't be 
done, then what's the right way to do what I want to do?

Here is my XSLT program:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
   xmlns:xs="http://www.w3.org/2001/XMLSchema";
   version="3.0">

   <xsl:template match="/">
       <xsl:variable name="list" select="(1, 2, 3)" as="xs:integer*" />
       <xsl:message>count($list) = <xsl:value-of 
select="count($list)"/></xsl:message>
       <xsl:variable name="document" as="element(Document)">
           <Document>
               <Greeting>My List</Greeting>
               <List><xsl:sequence select="$list" /></List>
               <Ending>The End</Ending>
           </Document>
       </xsl:variable>
       <xsl:message>count($document/List) = <xsl:value-of 
select="count($document/List)"/></xsl:message>
   </xsl:template>
</xsl:stylesheet>

/Roger

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