I think that, using a schema (for input & output documents) for an XSLT
transformation, in general is very useful. The main benefit is, I think,
stronger type checking of XML input/output data, which reveals many error
early during an XSLT transformation cycle.
On Mon, Jul 20, 2020 at 1:26 AM Martin Honnen
martin(_dot_)honnen(_at_)gmx(_dot_)de <
xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:
That expression will always return the number of "List" elements. If you
use a schema and give that element a list datatype then I think that
with schema-aware processing
$document/List/data()
would give you a list and you could of course count that list with e.g.
count($document/List/data())
So the simplest example would be
<xsl:import-schema>
<xs:schema>
<xs:element name="List" type="int-list"/>
<xs:simpleType name="int-list">
<xs:list itemType="xs:integer"/>
</xs:simpleType>
</xs:schema>
</xsl:import-schema>
<xsl:template match="/" name="xsl:initial-template">
<xsl:variable name="list" select="(1, 2, 3)" as="xs:integer*" />
<xsl:message>count($list) = <xsl:value-of
select="count($list)"/></xsl:message>
<xsl:variable name="list-element" as="schema-element(List)">
<List xsl:validation="strict">
<xsl:sequence select="$list"/>
</List>
</xsl:variable>
<xsl:message>count($list-element) = <xsl:value-of
select="count($list-element)"/></xsl:message>
<xsl:message>count($list-element/data()) = <xsl:value-of
select="count($list-element/data())"/></xsl:message>
<xsl:message select="$list-element instance of
schema-element(List)"/>
</xsl:template>
you would need to write a more complex schema for the more complex
sample you had I think, I am not sure whether you could use a schema
type for that element inside other untyped elements.
--
Regards,
Mukul Gandhi
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