You are reading it correctly. Note also that the very next bullet point
says:
A member to add to an existing object - whereupon the supplied
value is added to that object at the indicated location. If the
member already exists, it is replaced by the specified value.
So an "add" is really a "replace" that does not have the "target location
MUST exist" restriction. Personally, I'm not too fond of that decision. For
anything other than an array, "add" should fail if the target already
exists. For arrays, "add" should insert but never replace an existing
value.
- James
On Tue, Dec 11, 2012 at 7:25 AM, Barry Leiba
<barryleiba(_at_)computer(_dot_)org>wrote:
Abstract
JSON Patch defines the media type "application/json-patch", a JSON
document structure for expressing a sequence of operations to apply
to a JSON document, suitable for use with the HTTP PATCH method.
...
http://datatracker.ietf.org/doc/draft-ietf-appsawg-json-patch/
I've reviewed JSON Patch and JSON Pointer as responsible AD, and am
very happy with the documents -- this is good work, well written. I
came up with one issue that I want to discuss as part of last call:
4.1. add
The "add" operation adds a new value at the target location. The
operation object MUST contain a "value" member that specifies the
value to be added.
For example:
{ "op": "add", "path": "/a/b/c", "value": [ "foo", "bar" ] }
When the operation is applied, the target location MUST reference one
of:
o The root of the target document - whereupon the specified value
becomes the entire content of the target document.
Now, what this means is that if we start with this:
{ "a": { "num": 1 } }
and we apply this:
{ "op": "add", "path": "", "value": [ "foo", "bar" ] }
we end up with this:
[ "foo", "bar" ]
This doesn't strike me as having any sense of an "add" operation -- it
appears to be a special case that doesn't fit. In any other
situation, using any other path, the operation either adds something
to what's already there, or it fails. But when the path is "", it's
anomalous.
So, three questions:
1. Do I have this right, or am I mistaken about the result of that
operation?
2. Assuming I have it right, can someone explain why it's this way?
3. Can someone explain why this is the right way to specify it, rather
than using "replace" for this?
Barry
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