Re: using "\/" in "... ?? ..."

parv wrote:
> >   * Listid  ??  <\\/[a-z]+([-.a-z]+)?\.FreeBSD\.ORG
There is a double-\ there. I think it should be:

* Listid  ??  (<)\/[a-z]+(([-.][a-z]+)+)?\.freebsd\.org

if you mean a literal '<'.


If you made sure that Listid starts with the '<', then use: 

* Listid  ??  ^^(<)\/[a-z]+(([-.][a-z]+)+)?\.freebsd\.org


Ruud


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