The XSLT processor is looking for a resolvable path as the argument to the
document function.
If the value of the xlink:href attribute is a path to an actual XML file, then
it should work. If it isn't, and it's an IDREF-type link to attribute that
contains that value, then you'll need an XPath that will get that value for you.
w/o more information on your document structure ... It is a little hard on this
end ...
Rich
-----Original Message-----
From: Adam van den Hoven [mailto:list(_at_)adamvandenhoven(_dot_)com]
Sent: Tuesday, October 08, 2002 1:50 PM
To: XSL Mailing list
Sorry if this appears twice, I'm having some problems with my mail systems.
I have a question.
I want to use the following:
<xsl:apply-templates select="document('#id2')" />
Ok, I'd never actually use this. In reality its something like:
<xsl:apply-templates select="document(@xlink:href)" />
which is likely to contain simply fragment identifiers since I'm using XLinks
to normalize a sitemap hierarchy.
When I try to run this as part of a transform, I get an error saying that the
file (fully resolved to refer to the source doc) cannot be found. Is this a
problem with how I'm doing things or perhaps a problem with app I'm using to
develop templates with (Stylus Studio)?
Do you have any other ideas about how I can accomplish the same thing given
that some of my xlink:href attributes will point to external documents?
Thanks,
H. Adam van den Hoven
Web Developer
Credit Union Central of BC
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