Of course you can
write your own function to get the indexes of a node in a sequence of
nodes:
<xsl:function name="my:index-of" as="xs:integer*">
<xsl:param name="seq" as="node()*" />
<xsl:param name="item" as="node()" />
<xsl:for-each select="$seq">
<xsl:if test=". is $item">
<xsl:sequence select="position()" />
</xsl:if>
</xsl:for-each>
</xsl:function>
or use a for expression in an XPath:
for $i in (1 to count($seq))
return if ($seq[$i] is $item) then $i else ()
Two very nice ones, thanks Jeni!
There are lots of loc elements with identical attribute values,
only the text content of the element changing.
O date1
date2
date3
is the sort of svg I want.
I'd still want the 'position' in the group, to calculate the Y
offset for the text, so its not an improvement...
Erm... my point was that if you were processing the group as a whole
then you could use the position() function to get you the position of
the <loc> within the group. Something like:
<xsl:for-each-group select="loc" group-by="@hl">
<xsl:for-each-group select="current-group()" group-by="@side">
<xsl:for-each-group select="current-group()" group-by="@pos">
Ah!
That's clearer. I've just been fighting group-by="concat...
which fails :-)
I guessed it was possible.
Rather long winded?
Surprised the same ideas as the use attribute for keys isn't available.
<xsl:for-each select="current-group()">
position in group: <xsl:value-of select="position()" />
</xsl:for-each>
</xsl:for-each-group>
</xsl:for-each-group>
</xsl:for-each-group>
(I can't believe that no one apart from me is bothered about having to
nest <xsl:for-each-group> as in the above when you want to group by
several things at once.)
Is this a starter for ten for Jeni's own equivalent of Muenchian techniques?
Thanks Jeni.
regards DaveP
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