Hi! Bill
Your solution seems more logical.so I stopped.And
first gave it a try. But I could not use it, firstly
distinct-values() function raised an function not
found exception. Same happened with
<xsl:for-each-group. I know its an XSLT2.0 answer to
Muenchian Method.
I'am using Win2000 Professional on PIV machine
-XML SPY Professional v5 Rel2
-Apache FOP 0.20.5
-J2Sdk 1.4.2 with netbeans
-IE6 sp1
-Acrobat Reader 5.05
I changed in xslt file <xsl:stylesheet version="2.0"
but same error bombed
What else should I do to use XSLT2.0. Do I need to
install some thing?
should i post the actual code?
Regards,
Raj
--- Bill Keese <billk(_at_)tech(_dot_)beacon-it(_dot_)co(_dot_)jp> wrote:
(this is a resend; my original message bounced, I
think)
Problem: print a list of students, grouping the
students by their
language and printing a blank line between each
group. Number the blank
lines in addition to the lines with students' names.
So calling position() to get the number is
insufficient, because
position() doesn't count the blank lines.
Mukul was commenting that this problem would be
easier to solve if XSLT
supported something like variables. For example:
<xsl:for-each select="Student">
<xsl:if test="TOption !=
previous-sibling::Student[last()]/TOption">
<tr> <td> {counter} </td> <td/> <td/>
</tr>
counter++;
</xsl:if>
<tr> <td> {counter} </td> <td> {Name} </td>
<td> { Toption }
</td> </tr>
counter++;
</xsl:for-each>
This is what Jarno's code essentially does, but
Jarno had to use
recursion to simulate the loop, which is [arguably]
a bit cumbersome.
However, you can do something the loop above, if you
replace the
variable "counter" with a formula, which is
the previous number of students + the previous
number of groups
In XSLT version 2 this is simply:
count(preceding-sibling::*) +
count(distinct-values(preceding-sibling::*/TOption/text()))
And after the loop finishes, to compute the total
number of lines
printed, you would do
count(Student) +
count(distinct-values(Student/TOption/text()))
-------------
By the way, an alternative to a single loop is to
write a nested loop
(for-each language / for-each student). This is
what Americo's code
does, but his code is a bit complicated because he
is programming in
XSLT V1, where there is no for-each-group operator
(http://www.w3.org/TR/xslt20/#d0e15262) . But in
XSLT V2 we would say this:
<xsl:for-each-group select="Student"
group-by="TOption">
<xsl:variable name="group-no"
select="position()"/>
<xsl:for-each select="current-group()">
<tr>
<td> <xsl:value-of
select="count(preceding-sibling::*) +
$group-no"/> </td>
<td> <xsl:value-of select="Name"/> </td>
<td> <xsl:value-of select="TOption"/>
</td>
</tr>
</xsl:for-each>
<tr>
<td> <xsl:value-of
select="count(current-group()[last()]/preceding-sibling::*)
+ $group-no
+ 1"/> </td>
<td> </td>
<td> </td>
</tr>
</xsl:for-each-group>
Bill
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