Thanks mukul.
regards,
Ranjan
--- Mukul Gandhi <mukul_gandhi(_at_)yahoo(_dot_)com> wrote:
Please use exclude-result-prefixes
<xsl:stylesheet version="1.0"
xmlns:exslt="http://exslt.org/common";
xmlns:java="http://xml.apache.org/xslt/java";
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
exclude-result-prefixes="exslt java" >
The XSLT 1 spec says..
When a stylesheet uses a namespace declaration only
for the purposes of addressing the source tree,
specifying the prefix in the exclude-result-prefixes
attribute will avoid superfluous namespace
declarations in the result tree.
The value of exclude-result-prefixes is a
whitespace-separated list of namespace prefixes.
Regards,
Mukul
--- "Ranjan K. Baisak" <ranjanbaisak(_at_)yahoo(_dot_)com>
wrote:
My stylesheet generates an XML document. But the
xml
contains namespace declarations, which I don't
want.
The header part of my stylesheet is:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:exslt="http://exslt.org/common";
xmlns:java="http://xml.apache.org/xslt/java";
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" version="1.0"
encoding="UTF-8"
indent="yes"/>
The glimpse of xsl producing xml is:
<reportdetails>
<xsl:attribute name="name"><xsl:text>Chart
List</xsl:text></xsl:attribute>
<xsl:attribute name="generated"><xsl:value-of
select="java:java.util.Date.new()"/></xsl:attribute>
<xsl:attribute name="user"><xsl:value-of
select="$username"/></xsl:attribute>
</reportdetails>
and the output is:
<?xml version='1.0' encoding='UTF-8' ?>
<reportdetails
xmlns:java="http://xml.apache.org/xslt/java";
xmlns:exslt="http://exslt.org/common"; name="Chart
List" generated="Tue Feb 15 13:00:54 GMT+05:30
2005"
user=""/>
I don't want namespace declaration in the xml
file.
Any help would be appreciated.
regards,
Ranjan
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