I wrote:
To test if a node has siblings:
<xsl:if test="preceding-sibling::tree or following-sibling::tree">
Or:
<xsl:if test="../tree">
Of course the second one will always be true if the current node is a
<tree> node...
It would need to be modified to:
<xsl:if test="../tree[generate-id(.) != generate-id(current())]">
to ensure the the current <tree> node doesn't get included in the
selection.
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--