Given the following xml structure, I want to create an xsl if
element that tests the current node to see if it is a level 0
tree_node element.
<?xml version="1.0"?>
<tree>
<tree_node id="7" value="Test">
<tree_node id="8" value="Test Sub"/>
<tree_node id="9" value="Test Sub One">
<tree_node id="10" value="Test Sub Two"/>
</tree_node>
</tree_node>
</tree>
Here is my attached, pretty sad!!!!!
<xsl:if test="{count(self::*)=1}">
<xsl:apply-templates select="tree_node"/>
</xsl:if
Can someone give me the correct way to achieve this.
Also how can I found out if a particular node is a child,
ancestor or peer
Of any given node.
Thanks to anyone who response, muchly appreciated.
You need to read about the "xpath axis'" (plural)
To test if a node is the child of a tree node:
<xsl:if test="parent::tree">
To test if a tree node is the top-most tree node (dependant on
structure):
<xsl:if test="not(parent::tree)">
Or, (again depending on the structure of your xml):
<xsl:if test="not(ancestor::tree)">
To test if a node has siblings:
<xsl:if test="preceding-sibling::tree or following-sibling::tree">
Or:
<xsl:if test="../tree">
There are many, many ways. If you are certain of the structure of your
xml you could even do it at the template match level:
<xsl:template match="/tree">
(level 0 tree)
<xsl:template match="/tree/tree">
(level 1 tree)
...and so on.
cheers
andrew
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