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Node Position & Relationship!

2005-02-11 07:08:36
Given the following xml structure, I want to create an xsl if element that
tests the current node to see if it is a level 0 tree_node element.

<?xml version="1.0"?>
<tree>
  <tree_node id="7" value="Test">
      <tree_node id="8" value="Test Sub"/>
      <tree_node id="9" value="Test Sub One">
          <tree_node id="10" value="Test Sub Two"/>
    </tree_node>
  </tree_node>
</tree>


Here is my attached, pretty sad!!!!!

<xsl:if test="{count(self::*)=1}">
          <xsl:apply-templates select="tree_node"/>
</xsl:if      

Can someone give me the correct way to achieve this.
Also how can I found out if a particular node is a child, ancestor or peer 
Of any given node.

Thanks to anyone who response, muchly appreciated.

Cheers, 
Adam 
 
NB: "Pray as if everything depended upon God and work as if everything
depended upon man."



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