RE: grouping, sorting, splitting

> Is that something I'd need XSLT2.0 for or am I misunderstanding the
> RTF thing from XSLT1.0?
You can do multiphase transformations in 1.0 provided your processor offers
the xx:node-set() extension.

Alternatively, you can do each phase using a separate stylesheet.

Michael Kay
http://www.saxonica.com/

> On 4/18/05, Michael Kay <mike(_at_)saxonica(_dot_)com> wrote:
> > You should do this as a pipelined (or multi-phase) 
> transformation. Put the
> > results of the first grouping/sorting operation in a 
> variable (a temporary
> > tree) and then apply another transformation to put the 
> elements into groups
> > of three.
> >
> > Michael Kay
> > http://www.saxonica.com/
> >
> >
> > > -----Original Message-----
> > > From: beowulf [mailto:carisenda(_at_)gmail(_dot_)com]
> > > Sent: 18 April 2005 11:12
> > > To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
> > > Subject: [xsl] grouping, sorting, splitting
> > >
> > > Hi,
> > >
> > > I have XML if the form:
> > >
> > > <page>
> > > <entry date="2005-04-15">
> > >  <title>foo</title>
> > > </entry>
> > > <entry date="2005-04-15">
> > >  <title>bar</title>
> > > </entry>
> > > <entry date="2005-02-05">
> > >  <title>baz</title>
> > > </entry>
> > > ...
> > > </page>
> > >
> > > Which I am trying to group by date, sort by tiltle and 
> then split into
> > > sets of 3, 3 being the number of columns in the HTML 
> TABLE element I
> > > am trying to produce as an end result.
> > >
> > > I've got the grouping and sorting:
> > > <xsl:for-each select="entry[key('days', @date) and 
> count(.|key('days',
> > > @date)[1])= 1]">
> > > <xsl:sort select="title"/>
> > >
> > > and I've even got the first item in each group of three from that
> > > grouped and sorted set:
> > > <xsl:for-each select="key('days', @date)[position() mod 3 = 1]">
> > >
> > > But I just can't seem to make the final leap to displaying the
> > > following siblings of the above, making the 3 cell rows. 
> Should I be
> > > doing this some other way or can someone help me where I am?
> > >
> > > Many thanks,
> > > Stephen
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