A soap response contains a complex hierarchy of data, in which, if
the departure time is 00:45 hours then it is represented as 45 ! To
make matters worse, the schema defines it as a string. I have no
influence over the schema since I'm querying a webservice. So I need
to pad that 45 with 0s and of course add that colon. Is there a way I
can do that in XSL ?
Of course, but first one needs to know how other times are represented. Is
01:30 represented as "01:30", as "0130", as "90", or in some other way? And
is 00:05 represented as "5" or as "05"?
Furthermore, in the same repsonse, I have a string of the format
YYYYNYY [chars may be either Y or N], also respresented as a free
format string. This represents the days of the week starting from
Sunday... Now I need to take each char, and replace it with a <TD
color="green">S</TD> if it is Y, and <TD>S</TD> if it is N.
Anyway I can do that in XSL ?
Sure. In XSLT 2.0 do
<xsl:for-each select="1 to 7">
<TD>
<xsl:if test="substring($in, ., 1) = 'Y'">
<xsl:attribute name="color">green</xsl:attribute>
</xsl:if>
<xsl:text>S</xsl:text>
</TD>
</xsl:if>
In 1.0 the simplest solution is probably simply to unfold the loop, i.e.
repeat the content of the above for-each loop seven times changing the
second argument of substring() each time.
Michael Kay
http://www.saxonica.com/
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