On 9/21/05, Dimitre Novatchev <dnovatchev(_at_)gmail(_dot_)com> wrote:
Hi,
I think that trying to answer the following question can be interesting and
useful for the members of our community.
Is the following statement true or false:
"The transformation below is an identity transformation":
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output omit-xml-declaration="yes"/>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select="node()[1]"/>
</xsl:copy>
<xsl:apply-templates select="following-sibling::node()[1]"/>
</xsl:template>
</xsl:stylesheet>
On 9/21/05, Dimitre Novatchev <dnovatchev(_at_)gmail(_dot_)com> wrote:
Hi,
I think that trying to answer the following question can be interesting and
useful for the members of our community.
Is the following statement true or false:
"The transformation below is an identity transformation":
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output omit-xml-declaration="yes"/>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:apply-templates select="node()[1]"/>
</xsl:copy>
<xsl:apply-templates select="following-sibling::node()[1]"/>
</xsl:template>
</xsl:stylesheet>
I would say "yes" as it walks the tree in exactly the same way as the
standard identity transform.
The only difference here that I can see is that a no-op template would
stop all output on the following axis, instead of the descendant axis,
but I think that's just something to be aware of and not enough to say
this isn't an identity transform.
I hope this isn't going to be an anti-climax Dimitre...
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