You've confirmed that version="1.0", and I suspect despite what you say that
$in is untypedAtomic rather than xs:long. In the calculation, try wrapping
it as xs:integer($in).
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: xslt xslfo [mailto:xslt(_dot_)techie(_at_)gmail(_dot_)com]
Sent: 13 April 2006 17:52
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Convert milliseconds into date
This is what I am using;
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:fo="http://www.w3.org/1999/XSL/Format";
xmlns:xdt="http://www.w3.org/2005/02/xpath-datatypes";
xmlns:xs="http://www.w3.org/2001/XMLSchema";>
<xsl:value-of select="xs:dateTime('1970-01-01T00:00:00') + $in *
xs:dayTimeDuration('PT0.001S')"/>
The $in is date in "long" format which is passed as a paramter to the
XSL:FO. For testing, I have hardcoded the value to 1143230642199.
Does this help?
--------------------------------------------------------------
------------------------
I think this is what you would get if
(a) the stylesheet specifies version="1.0"
and
(b) the value of $in is untypedAtomic.
Since you haven't shown us the xsl:stylesheet element or the
declaration of
$in, this is just a hypothesis.
Michael Kay
http://www.saxonica.com/
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