The $in which is in milliseconds is an external parameter declared on
the stylesheet using <xsl:param>
The actual type of $in depends on whether you have declared the type in the
xsl:param declaration (I suspect you haven't, or you would have told us) and
on the object supplied in the invocation of the stylesheet. If you are
running from the command line, then the value will be untypedAtomic. If you
are running from a Java application, then it depends on what you supply in
the call: if you supply a Long, the value will be an xs:integer; if you
supply a String, it will be an xs:string.
Michael Kay
http://www.saxonica.com/
--------------------------------------------------------------
-------------------------------------------------------
You've confirmed that version="1.0", and I suspect despite
what you say
that
$in is untypedAtomic rather than xs:long. In the calculation, try
wrapping
it as xs:integer($in).
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: xslt xslfo [mailto:xslt(_dot_)techie(_at_)gmail(_dot_)com]
Sent: 13 April 2006 17:52
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Convert milliseconds into date
This is what I am using;
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:fo="http://www.w3.org/1999/XSL/Format";
xmlns:xdt="http://www.w3.org/2005/02/xpath-datatypes";
xmlns:xs="http://www.w3.org/2001/XMLSchema";>
<xsl:value-of select="xs:dateTime('1970-01-01T00:00:00') + $in *
xs:dayTimeDuration('PT0.001S')"/>
The $in is date in "long" format which is passed as a
paramter to the
XSL:FO. For testing, I have hardcoded the value to 1143230642199.
Does this help?
--------------------------------------------------------------
------------------------
I think this is what you would get if
(a) the stylesheet specifies version="1.0"
and
(b) the value of $in is untypedAtomic.
Since you haven't shown us the xsl:stylesheet element or the
declaration of
$in, this is just a hypothesis.
Michael Kay
http://www.saxonica.com/
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