xsl-list
[Top] [All Lists]

Re: [xsl] XML transformation based on parameters

2009-04-16 09:41:35


I'm tring to get the xml object as a string parameter, using
xx:evaluate()

you just seem to be blindly guessing. evaluate() is an extension
function that takes a string with xpath syntax and evaluates the xpath
expression. something like "/a/b[1]" If understand you correctly you
are passing in an in memory tree representing an XML document, so
evaluating it as xpath is not going to work.

But it appears that what you have is not an in memory tree but a string
with the xml source. So either invoke an xml parser before calling xalan
and then pass in teh result tree as a parameter, or pass in teh string
as a parameter and parse it using an extension function if xalan has an
extension (saxon has saxon:parse)


David


________________________________________________________________________
The Numerical Algorithms Group Ltd is a company registered in England
and Wales with company number 1249803. The registered office is:
Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom.

This e-mail has been scanned for all viruses by Star. The service is
powered by MessageLabs. 
________________________________________________________________________

--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--