[xsl] Re: Determining whether no single instance of a specific node exis

Sorry, my XSL examples weren't quite right.  I'm trying to determine
whether no instance of <c/> exists for each <b/> set.

So, in my XSL document, assume I'm processing each <a/> node.

1,
<xsl:when test="not(b/c)">

2.
<xsl:when test="count(not(b/c)) &gt;= 1">

Thanks,
Mark


On Thu, Jun 4, 2009 at 2:20 PM, Mark Peters 
<markpeters(_dot_)work(_at_)gmail(_dot_)com> wrote:
> Hi Everyone,
>
> I have the following XML document:
>
>     <a>
>             <b/>
>             <b/>
>             <b/>
>     </a>
>     <a>
>             <b/>
>             <b/>
>             <b>
>                     <c/>
>             </b>
>
>     </a>
>     <a>
>             <b/>
>             <b/>
>             <b/>
>     </a>
>
> For each <b/> set, I want to apply a transformation only if no single
> instance of <c/> exists. I know how to check whether a node does
> exist, but not how to check whether no single instance of the node
> exists.
>
> I've tried the following conditional statements without success:
>
> 1,
> <xsl:when test="not(a/b/c)">
>
> 2.
> <xsl:when test="count(not(a/b/c)) &gt;= 1">
>
>
> What conditional statement should I use?
>
> Thanks in advance for any help.
>
> Mark
--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--