test="not(b[not(c)])"
That worked! Thanks so much, David, for patiently figuring out what I
was trying to do, even though I couldn't articulate it clearly.
Best regards,
Mark
On Fri, Jun 5, 2009 at 9:16 AM, David
Carlisle<davidc(_at_)nag(_dot_)co(_dot_)uk> wrote:
I'm trying to determine whether no instance of <c/> exists for each
<b/> set.
what do you actually mean by this
test="not(b/c)"
is true if there are no c grandcildren.
If you mean that you want the test to be true unless
that every b child has a c child then that's
not the case taht there is a b that has not got a c so:
test="not(b[not(c)])"
David
________________________________________________________________________
The Numerical Algorithms Group Ltd is a company registered in England
and Wales with company number 1249803. The registered office is:
Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom.
This e-mail has been scanned for all viruses by Star. The service is
powered by MessageLabs.
________________________________________________________________________
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail:
<mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--