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RE: [xsl] Determining whether no single instance of a specific node exists

2009-06-04 14:52:35
Hello,

<xsl: if test="not(exists( (b/c) ) )" > ... </xsl:if>

Check other functions here:
http://www.w3schools.com/xpath/xpath_functions.asp#sequence

You can use all xpath functions in the if/when test condition. 

m.

-----Original Message-----
From: Mark Peters [mailto:markpeters(_dot_)work(_at_)gmail(_dot_)com] 
Sent: 4. júna 2009 20:21
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Determining whether no single instance of a specific node
exists

Hi Everyone,

I have the following XML document:

     <a>
             <b/>
             <b/>
             <b/>
     </a>
     <a>
             <b/>
             <b/>
             <b>
                     <c/>
             </b>

     </a>
     <a>
             <b/>
             <b/>
             <b/>
     </a>

For each <b/> set, I want to apply a transformation only if no single
instance of <c/> exists. I know how to check whether a node does
exist, but not how to check whether no single instance of the node
exists.

I've tried the following conditional statements without success:

1,
<xsl:when test="not(a/b/c)">

2.
<xsl:when test="count(not(a/b/c)) &gt;= 1">


What conditional statement should I use?

Thanks in advance for any help.

Mark

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