Indeed, I was going to add that the "real" way to do this under 1.0 was
XSLT sibling recursion, but I forgot.
Thanks David!
On Thu, Feb 18, 2021 at 4:35 PM David Carlisle
d(_dot_)p(_dot_)carlisle(_at_)gmail(_dot_)com <
xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:
I am facing an XPath problem
The answers so far have answered the question asked, but I wonder if that
is the wrong question.
To select the consecutive sequence of foo elements in xpath 1 requires
some kind of double pass over the list and quadratic behaviour in the
number of elements in the list.
However if (as appears the case) the question is in an XSLT context rather
than pure Xpath, you can usually avoid selecting the elements in a single
expression.
this does a single pass over the list stopping at the first non-foo
element so is linear complexity
xpath is just used to select one element at a time, the logic of handling
just foo elements is pushed to a specific XSLT mode that only handles foo
and stops at anything else,
Given
<x>
<b>
<foo>1</foo>
<foo>2</foo>
<bar>x</bar>
<foo>3</foo>
</b>
<b>
<foo>4</foo>
<foo>5</foo>
<foo>6</foo>
</b>
<b>
<bar>y</bar>
<foo>7</foo>
<foo>8</foo>
</b>
</x>
this stylesheet
<xsl:stylesheet version="1.0" xmlns:xsl="
http://www.w3.org/1999/XSL/Transform">
<xsl:template match="b">
<zzz>
<xsl:apply-templates mode="onlyfoo" select="*[1]"/>
</zzz>
</xsl:template>
<xsl:template mode="onlyfoo" match="*"/>
<xsl:template mode="onlyfoo" match="foo">
<xsl:copy-of select="."/>
<xsl:apply-templates mode="onlyfoo" select="following-sibling::*[1]"/>
</xsl:template>
</xsl:stylesheet>
produces
<zzz><foo>1</foo><foo>2</foo></zzz>
<zzz><foo>4</foo><foo>5</foo><foo>6</foo></zzz>
<zzz/>
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