Hi Mike!
I would strongly advise you to rework the problem, as there is no (IMHO)
clean way to do what you want to do. The following will work:
<xsl:variable name="myNode">
<xsl:copy>
<xsl:apply-templates .../>
</xsl:copy>
</xsl:variable>
<xsl:apply-templates select="vendor:node-set($myNode)"/>
Where vendor:node-set() is the implementation specific function to
convert an RTF to a node set.
Most problems like this can be solved in better ways, though...
HTH!
Dion
-----Original Message-----
From: Mike Carlisle [mailto:swflash(_at_)hotmail(_dot_)com]
Sent: Wednesday, September 18, 2002 3:09 PM
To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Can you apply a template match on a copy node?
Hello list people,
Wonder if anyone can help. I have an xsl which is applying templates on
match. One of these templates matches on an attribute. For various
reasons
within this template I want to copy the node (filtering out the matched
attribute), and then apply templates to the copy of this node.
How can I reference this copy? So far I have only been able to apply
attribute matches to my new node, not node matches.
Here's my code. It needs to write out the contents of the title
attribute,
make a copy of the node without the title attribute, and then apply
templates to this new copy.
<xsl:template match="*[(_at_)title]">
<xsl:value-of select="@title" />
<xsl:copy>
<xsl:apply-templates select="node()|@*[not(name(.) = 'title')]" />
</xsl:copy>
</xsl:template>
Any help is much appriecated.
Mike
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