Hi Mark,
//A[ contains(B/@a, "foo") ]
is going to return just A nodes that have B/@a with "foo" in it... so
it should actually return
<resp>
<A>
<B a="foo bar bar"></B>
<B a="bar bar foo"></B>
<B a="boo far far"></B>
</A>
<A>
<B a="far boo"></B>
<B a="foo bar foo"></B>
<B a="bar foo bar"></B>
</A>
</resp>
Because each of the A elements contain a B/@a with "foo" in it.
If you just want
<resp>
<A>
<B a="foo bar bar"></B>
<B a="bar bar foo"></B>
</A>
<A>
<B a="foo bar foo"></B>
<B a="bar foo bar"></B>
</A>
</resp>
Others correctly suggested //A[B[contains(@a, "foo")]]
But this will still just select the same 2 AA elements with the B
elements unchanged.
I think you want to do something like:
<xsl:for-each select=" //A[B[contains(@a, "foo")]]">
<A>
<xsl:apply-templates select="B[contains(@a, "foo")]"/>
</A>
</xsl:for-each>
This way you are selecting each of the desired A elements... and
filtering out the B elements that do not have the correct @a values.
Darcy
On Wed, Sep 3, 2008 at 1:27 PM, mark bordelon
<markcbordelon(_at_)yahoo(_dot_)com> wrote:
Dear Gents:
I have looked everywhere for the solution to this problem and never seem to
get what to the root of the issue. Here is the problem in a nutshell:
I have XML of this structure:
<resp>
<A>
<B a="foo bar bar"></B>
<B a="bar bar foo"></B>
<B a="boo far far"></B>
</A>
<A>
<B a="far boo"></B>
<B a="foo bar foo"></B>
<B a="bar foo bar"></B>
</A>
</resp>
Using XSLT 1.0 (which I must, since I am constrained to use ASP.NET 2.0) I
need to query the XML above to find all <A> if any of its children <B>
fulfill a certain requirement.
//A[ contains(B/@a, "foo") ]
What I am seeing is that this XSL only checks the FIRST child node's (B)
attribute instead of checking all of them. In other words, I only get this:
<resp>
<A>
<B a="foo bar bar"></B>
</A>
</resp>
...instead of what I need, namely this:
<resp>
<A>
<B a="foo bar bar"></B>
<B a="bar bar foo"></B>
</A>
<A>
<B a="foo bar foo"></B>
<B a="bar foo bar"></B>
</A>
</resp>
An attempt to alleviate this problem by amalgamating all the <B> together
using string-join, i.e.
//A[ contains( string-join(B/@a), "foo") ]
error-out because string-join is XSLT 2.0
So...what is the correct way to query through all child nodes using xslt 1.0?
Thanks Guys!
Sincerely,
Mark Bordelon
Getty Trust
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