OK. Very clear.
--- On Wed, 9/3/08, Darcy Parker <darcyparker(_at_)gmail(_dot_)com> wrote:
From: Darcy Parker <darcyparker(_at_)gmail(_dot_)com>
Subject: Re: [xsl] xslt 1.0 vs xslt 2.0 problem
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Date: Wednesday, September 3, 2008, 12:37 PM
No it shouldn't contradict what I said.
First you need to select the A nodes that have B elements with @a
containing 'foo'. (Everyone provided methods that can do this.)
Second, you then copy or recreate the A nodes but only copy/reproduce
the B sub-nodes that have @a containing 'foo'. (I think others will
agree with this, but neglected to see this as a requirement in your
first message.)
Darcy
On Wed, Sep 3, 2008 at 2:19 PM, mark bordelon
<markcbordelon(_at_)yahoo(_dot_)com>
wrote:
I did understand you mean the first node, not the first attribute.
Comprehension check: Does this at all contradict what Darcy wrote? I
don't think it does...but just making sure.
--- On Wed, 9/3/08, Andrew Welch
<andrew(_dot_)j(_dot_)welch(_at_)gmail(_dot_)com> wrote:
From: Andrew Welch <andrew(_dot_)j(_dot_)welch(_at_)gmail(_dot_)com>
Subject: Re: [xsl] xslt 1.0 vs xslt 2.0 problem
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Date: Wednesday, September 3, 2008, 11:17 AM
I wrote:
//A[contains((B/@a[1]), 'foo')]
but meant:
//A[contains((B/@a)[1], 'foo')]
...but hopefully you got the idea!
--
Andrew Welch
http://andrewjwelch.com
Kernow: http://kernowforsaxon.sf.net/
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