Dear Gents:
I have looked everywhere for the solution to this problem and never seem to get
what to the root of the issue. Here is the problem in a nutshell:
I have XML of this structure:
<resp>
<A>
<B a="foo bar bar"></B>
<B a="bar bar foo"></B>
<B a="boo far far"></B>
</A>
<A>
<B a="far boo"></B>
<B a="foo bar foo"></B>
<B a="bar foo bar"></B>
</A>
</resp>
Using XSLT 1.0 (which I must, since I am constrained to use ASP.NET 2.0) I need
to query the XML above to find all <A> if any of its children <B> fulfill a
certain requirement.
//A[ contains(B/@a, "foo") ]
What I am seeing is that this XSL only checks the FIRST child node's (B)
attribute instead of checking all of them. In other words, I only get this:
<resp>
<A>
<B a="foo bar bar"></B>
</A>
</resp>
...instead of what I need, namely this:
<resp>
<A>
<B a="foo bar bar"></B>
<B a="bar bar foo"></B>
</A>
<A>
<B a="foo bar foo"></B>
<B a="bar foo bar"></B>
</A>
</resp>
An attempt to alleviate this problem by amalgamating all the <B> together using
string-join, i.e.
//A[ contains( string-join(B/@a), "foo") ]
error-out because string-join is XSLT 2.0
So...what is the correct way to query through all child nodes using xslt 1.0?
Thanks Guys!
Sincerely,
Mark Bordelon
Getty Trust
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--