Re: [xsl] xslt 1.0 vs xslt 2.0 problem

I wrote:

> //A[contains((B/@a[1]), 'foo')]
but meant:

//A[contains((B/@a)[1], 'foo')]

...but hopefully you got the idea!




-- 
Andrew Welch
http://andrewjwelch.com
Kernow: http://kernowforsaxon.sf.net/

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