Re: [xsl] Referring to stylesheet itself, possible in XSLT 1.0, but how

On 10/17/06, Abel Braaksma <abel(_dot_)online(_at_)xs4all(_dot_)nl> wrote:
> David Carlisle wrote:
> > Incidentally, why do you want to use document('')??
>
> No reason in particular, other than getting the stylesheet that is
> currently being executed. I tried all sorts of ideas and combinations of
> ideas, but the result is simple: it cannot be done once you have the
> xsl:stylesheet offset to some directory where your current stylesheet
> does not reside.
>
> So, if your stylesheet uses something like this:
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
> version="2.0" xml:base="../..">
>
> but is itself not at location "../..", all bets are off for getting the
> location of the current stylesheet.
Instead of using xml:base why not just create a parameter $path and
then modify all of your paths in the stylesheet to contain that
parameter, eg:

<xsl:param name="path" select="'../../'" as="xs:string"/>

and

href="{$path}existingpath"


cheers
andrew

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