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RE: [xsl] Getting a list of node Text()

2007-06-19 15:51:40
-----Original Message-----
From: Nicholas Orr [mailto:nick(_at_)goya(_dot_)com(_dot_)au] 
Sent: 19 June, 2007 18:45
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Getting a list of node Text()

Essentially I'm trying to get a <Calculation> node which will 
be a child node of the current one.  But the issue is that 
there will sometimes be one calculation node, and sometimes 
multiple nodes.  And  
they're not always just child nodes, they might be sub child nodes.   
So I might have for my path :

./Calculation

or

./Value/Calculation
./StartPosition/Calculation

I think you are over thinking the problem.  If all you want is the
text from all the elements named Calculation then you should be
able to do:

./descendant-or-self::Calculation/text()


Andy.

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