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Re: Optimizing for what? Was Re: IETF Attendance by continent

2010-08-30 15:27:06
That is a well defined target metric.
It is defensible.
It is not the one the community has used up till now.
One could also aim to minimize total cost (or total pain).
Arguably, that would place all the meetings in california.

Up to till now, we have worked on a balance between those two objectives.

To take an extreme example, Olaf's argument would be equally valid if 1/10th of our active participants were from North America. But it would seem pretty silly to put 1/3 of the meetings in the North America in that case.

Yours,
Joel

Patrik Fältström wrote:
On 30 aug 2010, at 22.10, Melinda Shore wrote:

On Aug 30, 2010, at 12:05 PM, Patrik Fältström wrote:
On 30 aug 2010, at 21.57, Olaf Kolkman wrote:

If you want to be fair to the individual participants you have to optimize in 
such a way that attending 6 meetings costs the same for every individual that 
regularly attends the IETF. Obviously one can only approximate that by putting 
fairly large error bars on the costs but isn't the X-Y-Z distribution where X= 
approx Y= approx Z  the closest optimum? (or finding one place that sucks 
equally for everybody)
I agree with this finding.
It seems to me that a process like that would tend to lead
to incorrect results.  There's already bias in the population
of meeting attendees - do you, and, if so, how do you account
for people who are already not attending because of costs?

What Olaf wrote, if I did not misunderstand him, was that X=Y=Z, so that people 
living in the three regions each have to travel to say four meetings outside 
their region while getting two meetings inside their own region.

No connection to who goes to the IETF meetings today. Part from of course that 
we do not have Africa or South America as regions, and the poor people in 
Australia have to travel far for all meetings.

   Patrik

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