It's the same as doing
<xsl:if test="false()">
<xsl:value-of select="2 + 'London'"/>
</xsl:if>
Specifically: if there's a type error in an expression that would cause it
inevitably to fail if executed, then a static error can be reported
regardless of the fact that the expression will in fact not be executed.
Without this rule, you would get far fewer compile-time errors, which would
not be a good thing.
I presume this is actually generated code, since I can't imagine any
intelligent human writing it (unless perhaps to test the behaviour of the
processor). It's certainly true that type-checking rules make it harder to
generate code that will get through the compiler, but I think that's a price
worth paying.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Costello, Roger L. [mailto:costello(_at_)mitre(_dot_)org]
Sent: 28 April 2008 21:21
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Problem with iterating through a sequence of integers
Hi Folks,
Consider this for-loop which iterates through a sequence. If
the sequence value is a node then apply-templates is called.
Otherwise, the value is output:
<xsl:for-each select="(1, 2, 3)">
<xsl:choose>
<xsl:when test=". instance of node()">
<xsl:apply-templates select="." />
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="."/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
When I run Saxon, I get this error message:
Error: Required item type of @select attribute of
xsl:apply-templates is node(); supplied value has item type
xs:integer Failed to compile stylesheet. 1 error detected.
If I comment out the apply-templates statement, the for-loop works
fine.
It also works fine if I add a node to the for-loop's XPath expression,
e.g.
<xsl:for-each select="(//Book/Author, 1, 2, 3)">
I'm baffled. Any ideas?
/Roger
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